Topic 5.0: Sequence and series- Notes for form three
TOPIC 5: SEQUENCE AND SERIES
Sequences
The
Concept of Sequence
Explain
the concept of sequence
A
Sequence is the arrangement of numbers or is a list of numbers following a
clear pattern such that one number and the next are separated by comma (,).
Example:
a1, a2, a3, a4 ……………………..
NB:
Each number found in a Series or Sequence is called a term.
Example
1
Find
the next three terms in the following sequences.
5, 8,
11, 14, 17,………………………………
3, 7,
6, 10, 9, …………………………………
1, 2,
4, 7, ………………………………………
2, 9,
20, 35, …………………………………
Solution:
(a)You
can see that each term is less to the next by 3.
So
next three terms are (17+3),(17+3+3) and 17+3+3x3)
Which
are 20, 23, and 26
Alternately
add 4 and subs tract 1. The sequence then extends to 13, 12, 16
We
see that the difference is increasing by 1 each time. So the next three terms
are 11, 16 and 22.
The
differences are increased by 4 each time, so the next three terms are 54, 77
and 104.
Example
2
Write
down the first three terms in the sequences where the nth term is given by the
formulae.
Example
3
The
kth term of a series is k2 + 4
Find
the sum of the first four terms in the series
Solution:
k=1, k2+4=12+4=5
k=2,
k2+4=22+4=8
k=3,
k2+4=32+4=13
k=4,
k2+4=42+4=20
So
the series is 5+8+13+20 and its sum is 46
Example
4
Find
the nth term of the following sequences:
Exercise
1
1.
Write down the next three terms in the following sequences
2.
Find the first three terms in the sequence:
5n+2
1-3k
n2+n+1
2n
3.
Find the sum of the first four terms of the series where the kth term is given
by:
5k+3
k3-1
2k
4.
Find the nth term of these sequences:
An
Arithmetic Progression (AP) and Geometric Progression (GP)
Identify
an arithmetic progression (AP) and geometric progression (GP)
When
the series or sequence is such that between two consecutive terms there is a
difference which is fixed, then the series or sequence is called an arithmetic
progression (A.P)
The
fixed difference (number) between two consecutive terms is called the common
difference (d)
Example
5
In
the sequence 4, 7, 19, 13, 16 there is a common difference which is
7-4=10-7=13-10=16-13=3.
So
the common difference (d)=3.
Note
that in arithmetic progression (A.P) the difference between two successive
terms is always the same.
Sometimes
numbers may be decreasing instead of increasing, the arithmetic sequence or
series while terms decrease have a negative number as a common difference.
Example
6
The
common difference of the sequence 6, 4, 0, -2, …………………… is
4-6=2-4=0-2=-2-0=-2
So
the common difference is -2.
In
general if A1, A2, A3, A4, ……………………… An are the terms of the arithmetic
sequence , then the common difference is ;
Example
7
For
each of the following sequences, find the common difference and write the next
two terms.
Solution:
Exercise
2
1.
Find the common difference for each of the following sequence:
11,
14, 17, 20, …………………………………
2, 4,
6, 8, 10, ……………………………………
0.1,
0.11, 0.111, 0.1111 , …… … … … … …
y,
y+3, y+6, y+9, y+12, … …… … … … ……
2.
State whetherthe following sequence are arithmetic or not:
2, 5,
8, 11, 14, …………… ……………… ……
1, 3,
4, 6, 7, 9, 10, ………………………………
y, y
+ x, y+2x, y+3x, … ………… ……
3.
The temperatureat a mid day is 30c, and it falls by 20c each hour. Find the
temperature at the end of the next four hours.
Geometric
Progression (G.P).
When
the series or Sequence is such that between two consecutive terms there is a
ration which is fixed, then the series or sequence is called a geometric
progression (G.P)
The
fixed ratio(number) between two successive terms is called the common ratio
(r).
Example
8
In 2,
4, 8, 16, 32, … … …… … … …….
There
is a common ration which is
Note
that like in arithmetic progression (A.P), in geometric progression (G.P) the
common ratio does not change.
Also
the terms may be decreasing instead of increasing, the geometric sequence or
series whose terms decrease have a positive common ratio which is less than 1
for the progression with positive terms.
Example
9
For
each of the following sequence find the common ratio.
Example
10
For
the following geometric sequences, find the common ratio and write down the
next two terms:
The
next term is found by multiplying the term considered to be the last term by
the common ratio.
Exercise
3
1.
Which of the following sequences are geometric
1, 2,
4, 8, 16, ……………………………………
2, 6,
18, 54, 162, …………………………………
1,
-1,1,-1,1, ………………………………………
x2,
2x3, 4x4, 8x3…………………………………
1, 2,
4, 7, 10, ………………………………………
0.1,
0.2, 0.3, 0.4, 0.5, ……………………………
3, 6,
9, 12,15, ……………………………………….
2.
Find thecommon difference for each of the following geometric progressions
(G.P)
3.
Find thenext term of the sequence 2, 10, 50, 500,………………….
4.
The populationof a town is decreasing so that every year the population
declines by a quarter. If the population is originally 100,000. What will it be
after 5 years?
The
General Term of an AP
Find
the general term of an AP
If
A1, A2, A3, …………………An are the terms of an arithmetic sequence, then there is a
common difference d which is given by
d =
A2 – A1 = A3 – A2 = An – An – 1
But .
A3 = A1 + 2d which means
A4 =[
A1+2d]+d
= A1
+ 3d
Putting
into consideration this pattern, it is true that
A5 =
A1 + 4d
A6 =
A1 + 5d
An =
A1 + (n-1)d
Where
An is the nth term
The
nth term of the sequence with first term A1 and common difference d is given by
Example
11
Find
theformula for the nth term of the sequence 8 , 9.5, 11, 12.5, 14, 15.5,……
Note
that the nth term gives every term in the sequence,
For
example when n=3, you have A3=1.5x3+6.5=11
So
A3=11 where 11 is given in the sequence above having the third position.
Therefore
An shows the position of the term in sequence and of A1+(n-1)d gives the value
of the term for any positive integer.
Example
12
The
5th term of an arithmetic sequence is 11, and the 8th term is 26. Find the
first five terms.
Example
13
The
8th term of an arithmetic sequence is 9 greater than the 5th term, and the 10th
term is 10 times the 2nd term. Find
The
common difference (d)
20th
term.
The
General Term of GP
Find
the general term of GP
If
G1, G2, G3,……………..Gn are the terms of a geometric sequence, then they have a
common ratio (r) which is given by
Example
14
Find
the formula for the nth term of each of the following geometric sequence.
2, 6,
18, 54 , ………………………………
4,-2,
1, -0.5, 0.25 …………………………
Example
15
Considering
that,
Exercise
4
1. In
the arithmetic sequence, the 17th term is 30 and 9th term is 42 find the first
three terms.
2. In
the Arithmeticsequence the third term 12 and the 9th term 24. Find the nth term
of the sequence and use it to find the 15th term.
3.
Find the15th term of the sequence 5, 10, 20, 40 ,…………………………
4. A
population isincreasing and every year it is multiplied by 1.03. If it starts
off at 10,000,000, what will it be after n years?
5. The first termof the geometric sequence is 7 and the common ratio is 4. What is the 9th term of this sequence?
Series
The
Formula for a Sum of an Arithmetic Progression
Derive
the formula for a sum of an arithmetic progression
When
the terms are separated by addition (+) sign, there we have what we call a
series.
Example:
2+4+6+8+……………………………
Is a
series with the first term (A1) 2 and common difference (d) 2
It is
possible to establish a formula for the sum of the first n terms of the
arithmetic progression.
Let
Sn denote the sum of the first n terms of the arithmetic series.
Consider
the sum of the first 5, terms of arithmetic progression (AP) whose first term
is 1 and whose common difference (d) is 1.
So S5
= A1+A2+A3+A4+A5
S5=1+2+3+4+5
………………………….. (1)
The
first case is the sum of five terms which are increasing from 1 up to 5 while
the second case shows the same sum but the terms are decreasing from 5 to 1.
If
you add (1) and (2) together, you find that
S5+S5=(1+5)
+ (2+4) +(3+3) + (4+2) + (5+1)
25s =
6+6+6+6+6
255=30
Dividing
by 2 each side gives
Also
we can write
Example
16
Findthe
sum of the first 20 terms of the series
Example
17
Find
the sum of the series 4+7+10+13+…………….+304
Solution:
To
use the formula for summation of n terms, you must know how many terms are
there, i.e finding the value of n;
Now
A1=4,
d=3 and An = 304 n=?
An
=A1+ (n-1)d
304 =
4+ (n-1)x3
304 =
4+3n-3
304=3n+1
304=3n
Example
18
How
many terms of the series 1+3+5+7+………………. are needed to make the sum of 169?
Exercise
5
1.
Find thesum of the first 20 terms of the series
2+5+8+11+……………………
19+16+13+10+7+……………
2.
Find thenumber of terms and the sum of the series:
1+3+5+7+
……………………………………
40+37+34+31+…………………+-257
3.
The sumof the first 10 terms of an arithmetic progression (A.P) is 40, and the
sum of the next 10 terms is 80. Find the sum of the first five terms of the
series.
4.
One dayFrola spends 40 minutes of her home work. The length of time she spends
increase by 4 minutes each day. Find the total length of time she spends after
eight days.
The
Arithmetic Mean
Calculate
the arithmetic mean
Remember
that the arithmetic mean (M) of n numbers is found by adding them and then
dividing the sum by n, e.g the arithmetic mean of a,b,c and d is
The
Formula for the Sum of a Geometric Progression
Derive
the formula for the sum of a geometric progression
Geometric
series are the series that can be written as
G1+G2+G3+
………………………..Gn
Example:
2+4+8+16+ ………………………..+Gn
Or 1+3+9+27+81+…………………….
Suppose
we want to find the sum of 1+3+9+9+27+81+…………………
S5=!+3+9+27+81……………………….(1)
If we
multiply sn by the common ratio(r), we have.
Example
19
1.
Find the sum of the geometric series 2+4+8+ ………………..+2048
Example
20
Find
the sum of the first 8 terms of the series 5+20+80+320+ ……………
Exercise
6
1.
For each ofthe following series, find the number of terms and hence the sum of
the series.
1+3+9+…………………+729
1-2+4-8+………………+1,024
The
Geometric Mean
Calculate
the geometric mean
The
Geometric mean (GM) of n positive numbers is found by taking the nth root of
their product.
Example
21
The
Geometric mean of a, b, c and d is
The
arithmetic mean and geometric mean can be used to check that a sequence is an
arithmetic or geometric respectively.
FACTS:
If a,
b and c are consecutive three term of arithmetic progression (A.P), then b is
the arithmetic mean of a and c
If a,
b and c are three consecutive terms of geometric progression (G.P), then b is
the geometric mean (G.M) of a and c.
Proof:
Example
22
Find
the arithmetic and geometric means of
Exercise
7
1.
Find the arithmetic and geometric means of the following;
x1,
x3
4x,
9x
4a,
25a.
2.
The arithmeticmean and geometric mean of two numbers are 7.5 and 6
respectively. Find the two numbers.
Compound
Interest
Compound
Interest using Formula
Calculate
compound interest using formula
Suppose
money is invested or borrowed. At the end of a year, interest is calculated.
Suppose this interest is added to the original principal, and at the end of the
next year interest is added to the new principal. This process may be continued
for a number of years.
This
process is called COMPOUND INTEREST.
When
money is invested at a compound interest, the amount of money increase as a
geometric sequence.
Example
23
Ibrahimu
invested 20,000/= at 6% compound interest. How much was there after 5 years?
Now
let the principal be P, the rate R% and the time in years be n.
Example
24
At
the beginning of each year Martha invests 10,000/= at 5% compound interest. How
much does she have at the end of the 10th year?
Solution:
She
has made 10 different investments each giving different amount of interest.
The
1st investment has had 10 years of interest, hence it is 10,000 x (1.05)10
The
2nd investment has had 9years of interest. So it is 10,000 x (1.05)9
The
3rd investment has had 8 years of interest. Hence it is 10,000 x (1.05)8
Following
this pattern,
The
10th investment has had 1 year of interest. Hence it is 10,000x1.05.
The
sum of all these amounts is given by;
10,000x1.0510
+10,000 x1.059+ 10,000x1.058+……………+10,000x1.05
This
geometric series with first term 10,000 x 1.05 and common ratio 1.05.
Exercise
8
1.
Find thetotal amount of the following savings if they earn compound interest.
100,000/=
for 2years at 6% p.a
250,000/=
for 3 years at 4.5% p.a
400,000/=
for 20years at 5.5% p.a
2. A
populationis increasing at 2% if it starts at 10,000,000 what will it be after
20 years.
3. At
the beginning of each year 600,000/= is invested at 6% compound interest.Find
the total value of the investment at the end of the 15th year.